Alloy

The first alloy is a mixture of two metals in the ratio 1:2, the second is a mixture of same metals in the ratio 2:3. At what ratio we have these two alloys put into the furnace to obtain a new metal alloy with ratio 17:27? (All three ratios correspond to the same order of the two metals).

Correct answer:

r =  9:35

Step-by-step explanation:

k1=11+2 m1+22+3 m2 k2=21+2 m1+32+3 m2  k1=13 m1+25 m2 k2=23 m1+35 m2  k1/k2=17:27 r=m1/m2  17/27=13 m1+25 m223 m1+35 m2  17 (23 m1+35 m2)=27 (13 m1+25 m2) 17 (23 r+35)=27 (13 r+25)  r=27 2517 3517 2327 13=9350.2571   Verifying Solution:  m1=9 kg m2=m1/r=9/0.2571=35 kg  k1=13 m1+25 m2=13 9+25 35=17 kg k2=23 m1+35 m2=23 9+35 35=27 kg  t2=k1/k2=17/27=17270.6296



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