# Cars

Cars started at 7:00 AM.
From point A car run at 40 km per hour, from B car run 70 km per hour. Between A and B is 250 km long road.

When and where will meet (measured from point A)?

Result

T = 9:16 hh:mm
s1 =  90.91 km

#### Solution:

$s_1 = v_1 t \ \\ s_2 = v_2 t \ \\ s = s_1+s_2 = v_1 t + v_2 t = t(v_1+v_2) \ \\ t = \dfrac{s}{v_1+v_2} = \dfrac{ 250}{ 40+70 } = 2.27 \ h \ \\ T = 7 + t = 9:16 \ \text{hh}:\text{mm}$
$s_1 = v_1 t = 40 \cdot 2.27 = 90.91 \ \text{km}$

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