Started 81404

At 7:30 AM, the bus left at a speed of 45 km/h, and at 8:00, a car behind it started at 65 km/h. Where and when did they meet?

Result

s =  73.125 km
t = 9:08 hh:mm Wrong answer

Step-by-step explanation:

v1=45 km/h t1=7:30=7 hr 30 min =7+6030=7.5 hr=7.5  v2=65 km/h t2=8:0=8 hr =8  s1=s2=s  v1 (tt1)=v2 (tt2) 45 (t7.5)=65 (t8)  20t=182.5  t=20182.5=9.125  t=873=9.125  s=v1 (tt1)=45 (9.1257.5)=73.125 km



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