Where and when

The truck left Kremnica at 11:00 h at a speed of 60km/h. At 12:30 h, the passenger car started at an average speed of 80km/h. How many kilometers from Kremnica will the passenger car reach truck, and when?

Result

s =  360 km
T = 17:00 hh:mm Wrong answer

Solution:

s1=s2 v1=60 km/h v2=80 km/h    v1⋅ (t−11.00)=v2⋅ (t−(12+30/60)) 60⋅ (t−11.00)=80⋅ (t−(12+30/60))  1200t=20400  t=17  s=v1⋅ (t−11.00)=60⋅ (17−11.00)=360=360 km   Verifying Solution:  s2=v2⋅ (t−12.50)=80⋅ (17−12.50)=360 km s1=s2=s
T=t=17=17:00 hh:mm

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