Window
Peter knocked a 100 × 67 cm opening in the wall for a window frame. When the glazier installs the frame and glass, the glass will be 13.5 cm from the edge of the opening on each side.
By what percentage less light enters through the glass than through the full opening?
By what percentage less light enters through the glass than through the full opening?
Final Answer:

Tips for related online calculators
Our percentage calculator will help you quickly and easily solve a variety of common percentage-related problems.
You need to know the following knowledge to solve this word math problem:
planimetrybasic operations and conceptsGrade of the word problem
We encourage you to watch this tutorial video on this math problem: video1
Related math problems and questions:
- Glass cost
We had eight panes of glass cut by the glazier. Each had the shape of a square with a side of 18 cm. We paid 44 CZK. How much does 1 m² of glass cost? - Glass panel
A rectangular glass panel with 72 cm and 96 cm dimensions will cut the glazier on the largest square possible. What is the length of the side of each square? How many squares does the glazier cut? - Wallpapering a room
The walls of a room are to be covered with wallpaper from floor to ceiling. The room is rectangular. It is 3 m wide, 5 m long, and 2.5 m high. In one wall there is a door, which together with the frame occupies a rectangle with dimensions 80 cm and 2 m. I - Glass
Peter broke the window glass with sizes 110 cm and 90 cm. One square meter of glass costs 15 Euro. How much money is needed to buy new glass? - Square glass
What is the square window glass area with the side 4 dm? Do you know how many cm² is? - Safe wall percentage
The safe is 100 cm high, 80 cm wide, and 60 cm deep. Its internal space has a volume of 168 liters. What percentage of the total volume of the safe is occupied by the walls of the safe? - Quadrilateral pyramid
The regular quadrilateral pyramid has a surface of 260 cm² and a side wall area of 40 cm². Calculate the length of the base edge and the wall height.
