# Window

Peter demolish box hole in the wall for window frame 147×51 cm. When they came masters fitted frame and window will be found that glass is 13.3 cm from the hole in each direction.

Calculate how much percent less light enters the window than hole?

Result

p =  60.8 %

#### Solution:

$p=100\% \cdot \dfrac{S_1-S_2}{S_1} = \ \\ = 100\% \cdot \dfrac{ 147\cdot51-(147-2\cdot13.3)\cdot(51-2\cdot13.3) }{ 147\cdot51 } = \ \\ = 60.8 \%$

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