Quadrilateral

In the square ABCD point P is in the middle of the DC side and point Q in the middle pages AD. If the area of quadrilateral BQPC is 49 cm2, what is the area of ABCD?

Correct result:

S =  78.4 cm2

Solution:

S=a2  a212a2a212aa2=49 a218a212a2=49 58a2=49 a2=4985=78.4 cm2 S=a2=78.4 cm2



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