In the square ABCD point, P is in the middle of the DC side, and point Q is in the middle of side AD. If the area of quadrilateral BQPC is 76 cm2, what is the area of ABCD?

Correct answer:

S =  121.6 cm2

Step-by-step explanation:

S1=76 cm2  S = a2 a2  21 (a/2) (a/2)  21 a (a/2) = S1 a2  81 a2  21 a2 = S1  85 a2 = S1 S = a2 = 58 S1  S=58 S1=58 76=58 76=5608=5608 cm2=121.6 cm2

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