Lottery

Pavol has two lottery tickets, each from a different lottery. The first lottery has 1203 thousand tickets, of which 410 thousand are winners. The second lottery has 1478 thousand tickets, of which 1478 thousand are winners. What is the probability that at least one of Pavol's tickets wins?

Final Answer:

p =  66.4163 %

Step-by-step explanation:

p1=410/1203=12034100.3408 p2=725/1478=14787250.4905  r=p1+p2p1 p2=0.3408+0.49050.3408 0.49050.6642  p=100 r=100 0.6642=66.4163%



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