Find quotient before the bracket - the largest divisor
51 a + 34 b + 68

Correct result:

d1 =  17
d2 =  11


51=317 34=217 68=2217 GCD(51,34,68)=17  d1=GCD(51,34,68)=17  51a+34b+68=17(3a+2b+4)
121=112 99=3211 33=311 GCD(121,99,33)=11  d2=GCD(121,99,33)=11  121y99z+33=11(11y9z+3)

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