Building

The building I focused at an angle 30°. When I moved 5 m building I focused at an angle 45°. What is the height of the building?

Result

x =  6.8 m

Solution:

$\tan 30 ^\circ = x/y \ \\ \tan 45 ^\circ = x/(y-5) \ \\ \ \\ \tan 45 ^\circ = x/(x/\tan 30 ^\circ - 5) \ \\ \ \\ x= \dfrac{ 5 \cdot \tan (45^\circ)}{ \dfrac{ \tan (45^\circ)}{\tan (30^\circ)} -1} = 6.8 \ \text{m}$

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