Ratio of perimeters

Rectangle ABCD has dimensions 3 cm and 4 cm, KLMN rectangle has dimensions 4 cm and 12 cm. Calculate the ratio of the perimeter ABCD and perimeter KLMN.

Result

p =  0.438

Solution:

p=2(a+b)2(k+l)=3+44+12=0.438p = \dfrac{ 2(a+b) }{ 2(k+l) } = \dfrac{ 3+4}{ 4+12} =0.438

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