A drone

A flying drone aimed the area for an architect. He took off perpendicularly from point C to point D. He was 300 m above ABC's plane. The drone from point D pointed at a BDC angle of 43°. Calculate the distance between points C and B in meters.

Final Answer:

x =  279.7545 m

Step-by-step explanation:

$$\begin{gathered} CD=300\text{m} \\ \angle BDC=43{}^{\circ } \\ \angle DCB=90{}^{\circ } \\ \delta =BDC°\to \text{rad}=BDC°\cdot \frac{\pi }{180}=43°\cdot \frac{3.1415926}{180}=0.75049 \\ \tan \delta =BC/CD \\ \tan \delta =x/CD \\ x=CD\cdot \tan (\delta )=300\cdot \tan (0.7505)=279.7545\text{m} \end{gathered}$$

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