A drone

A flying drone aimed the area for an architect. He took off perpendicularly from point C to point D. He was at the height of 300 m above ABC's plane. The drone from point D pointed at a BDC angle of 43°. Calculate the distance between points C and B in meters.

Correct answer:

x =  279.7545 m

Step-by-step explanation:

$$\begin{gathered} CD=300\text{ m } \\ BDC=43\text{ ° } \\ DCB=90\text{ ° } \\ \delta =BDC\mathrm{°}\to \text{ rad}=BDC\mathrm{°}\cdot {\displaystyle \frac{\pi }{180}}=43\mathrm{°}\cdot {\displaystyle \frac{3.1415926}{180}}=0.75049 \\ \tan \delta =BC\mathrm{/}CD \\ \tan \delta =x\mathrm{/}CD \\ x=CD\cdot \tan (\delta )=300\cdot \tan (0.7505)=279.7545\text{ m} \end{gathered}$$

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