Observation 17433

The aircraft flying just above point A can be seen from observation B, 2,400 meters away from point A, at an altitude of 52°30'. How high does the plane fly?

Correct answer:

h =  3127.7409 m

Step-by-step explanation:

$$\begin{gathered} x=2400\text{m} \\ \alpha =52+30/60=\frac{105}{2}=52.5{}^{\circ } \\ \tan \alpha =h:x \\ h=x\cdot \tan \alpha =x\cdot \tan 52.5°=2400\cdot \tan 52.5°=2400\cdot 1.303225=3127.741=3127.7409\text{m} \end{gathered}$$

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