Worker's performance

15 workers paint 180 m fence in 3 days. In how many days will 9 workers paint a 360 m fence? We assume that each worker have the same, constant and unchangeable performance.

Result

x =  10 d

Solution:

r=180/(3⋅ 15)=4 m/d/r l=360 m  x=l/(9⋅ r)=360/(9⋅ 4)=10 dr=180/(3 \cdot \ 15)=4 \ \text{m/d/r} \ \\ l=360 \ \text{m} \ \\ \ \\ x=l/(9 \cdot \ r)=360/(9 \cdot \ 4)=10 \ \text{d}

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