Two workers

Two workers carry will do certain work for 12 days. After 8 days of working was one removed, and then the other finished the job alone in 10 days.

For how many days would do this work alone each worker?

Correct result:

a =  20 d
b =  30 d

Solution:

12(1a+1b)=1 8(1a+1b)+101b=1  8112+10b=1 b=10/(18/12)=30 d  12(1a+1b)=1 12(1a+130)=1 a=1112130=20 d
b=10/(18/12)=30 d



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