Parquet floor

Three workers laid parquet floor for 2.301 hour. The first one would do this work alone 7 hours, the second in 6 hours.

For how many hours would fulfill this work the third worker, if he worked alone?

Correct result:

x =  8 h

Solution:

2.301 (1/7+1/6+1/x)=1   2.301 (x/7+x/6+1)=x  12.087x=96.642  x=7.995532=8 h



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