# Parquet floor

Three workers laid parquet floor for 2.301 hour. The first one would do this work alone 7 hours, the second in 6 hours.

For how many hours would fulfill this work the third worker, if he worked alone?

Result

x =  8 h

#### Solution:

$2.301 \cdot \ (1/7 + 1/6 + 1/x)=1 \ \\ \ \\ \ \\ 2.301 \cdot \ (x/7 + x/6 + 1)=x \ \\ \ \\ 12.087x=96.642 \ \\ \ \\ x=7.995532 \ \\ =8 \ \text{h}$

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