Turners

Two turners perform joint work in 3 hours. The first turner would perform the job himself in 7 hours. How long would the same job last for a second turner if he worked alone?

Correct result:

x =  5.25 h

Solution:

3 (1/7+1/x)=1 x/7+1=x/3 0.190476x=1 421x=1 4x=21 x=21/4=5.25 =214 h=5.25 h



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