Construction 64524

The bricklayer and the apprentice will build the wall in 6 hours. If the bricklayer worked alone, the wall construction would take him 5 hours shorter than the apprentice. How long before the wall would the bricklayer build himself?

Correct answer:

a =  10 h

Step-by-step explanation:

6   (1/a + 1/b) = 1 a = b5  6   (1/a + 1/(a+5)) = 1  6 ((a+5)+a)=(a+5) a  6 ((a+5)+a)=(a+5) a a2+7a+30=0 a27a30=0  p=1;q=7;r=30 D=q24pr=7241(30)=169 D>0  a1,2=2pq±D=27±169 a1,2=27±13 a1,2=3.5±6.5 a1=10 a2=3  a=a1=10=10 h   Verifying Solution:  b=a+5=10+5=15 h t=6 (a1+b1)=6 (101+151)=1

Our quadratic equation calculator calculates it.




Did you find an error or inaccuracy? Feel free to write us. Thank you!







Tips for related online calculators
Are you looking for help with calculating roots of a quadratic equation?
Need help calculating sum, simplifying, or multiplying fractions? Try our fraction calculator.
Do you have a linear equation or system of equations and looking for its solution? Or do you have a quadratic equation?
Do you want to convert time units like minutes to seconds?

You need to know the following knowledge to solve this word math problem:

Units of physical quantities:

Themes, topics:

Related math problems and questions: