Three co-owners

The three co-owners of building company have earnings from a contract portioned in the ratio of 3:6:7. Each of them received the amount in whole USD. One of them on contract earned 86450 USD. What was the total earnings this order?

Result

x =  197600

Solution:

k1=1/3(3+6+7)86450=461066.66666667 k3=1/6(3+6+7)86450=230533.33333333 k3=1/7(3+6+7)86450=197600 x=197600k_1 = 1/3\cdot (3+6+7)\cdot 86450 = 461066.66666667 \ \\ k_3 = 1/6 \cdot (3+6+7) \cdot 86450 = 230533.33333333 \ \\ k_3 = 1/7 \cdot (3+6+7) \cdot 86450 = 197600 \ \\ x = 197600



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