Three co-owners

The three co-owners of the building company have earnings from a contract portioned in the ratio of 3:6:7. Each of them received the amount in the whole USD. One of them, on contract, earned 86450 USD. What were the total earnings for this order?

Final Answer:

x =  197600 Kc

Step-by-step explanation:

$$\begin{gathered} z=86450\text{Kc} \\ y=(3+6+7)\cdot z=(3+6+7)\cdot 86450=1383200\text{Kc} \\ {k}_1=1/3\cdot y=1/3\cdot 1383200\doteq 461066.6667 \\ {k}_3=1/6\cdot y=1/6\cdot 1383200=197600 \\ {k}_3=1/7\cdot y=1/7\cdot 1383200=197600 \\ x=k_3=197600=197600\text{Kc} \\ \text{ Verifying Solution: } \\ a=\frac{3}{3+6+7}\cdot x=\frac{3}{3+6+7}\cdot 197600=37050\text{Kc} \\ b=\frac{6}{3+6+7}\cdot x=\frac{6}{3+6+7}\cdot 197600=74100\text{Kc} \\ c=\frac{7}{3+6+7}\cdot x=\frac{7}{3+6+7}\cdot 197600=86450\text{Kc} \end{gathered}$$

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