# Juice box 2

Box with juice has the shape of a cuboid. Internal dimensions are 15 cm, 20 cm and 32 cm. If the box stay at the smallest base juice level reaches 4 cm below the upper base. How much internal volume of the box fills juice? How many cm below the top of the base will reach the level of juice if the box flip 90° around its shortest side?

Result

V =  8.4 l
x =  2.5 cm

#### Solution:

$V=(15 \cdot \ 20 \cdot \ 32-4 \cdot \ 15 \cdot \ 20)/1000=\dfrac{ 42 }{ 5 }=8.4 \ \text{l}$
$x=4 \cdot \ 15 \cdot \ 20/15/32=\dfrac{ 5 }{ 2 }=2.5 \ \text{cm}$

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