Route passes trapezoidal orchard perpendicular to the parallel sides. It is 80 cm wide. The lengths of the bases are in the ratio 5:3 and the length of the longer base to the length of the path is in the ratio 5:6. How many square meters occupies the route if the entire acreage is 5400 square meters?

Correct result:

S =  72 m2


S=0.8h  5400=a+c2h a=5x c=3x h=6x 5400=5x+3x26x 10800=48x2 225=x2 x=15 a=75 m b=45 m h=90 m S=0.890=72 m2 

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