Orchard

The route passes the trapezoidal orchard perpendicular to the parallel sides. It is 80 cm wide. The lengths of the bases are in the ratio 5:3. The length of the longer base to the size of the path is in the ratio of 5:6. How many square meters occupy the route if the entire acreage is 5400 square meters?

Correct answer:

S =  72 m2

Step-by-step explanation:

w=80 cm m=80:100  m=0.8 m A=5400 m2  A = 2a+c  h a = 5x c = 3x h = 6x  5400 = 25x + 3x  6x 10800 = 48 x2  x=10800/48=15 m  a=5 x=5 15=75 m b=3 x=3 15=45 m h=6 x=6 15=90 m S=w h=0.8 90=72 m2



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