Moivre 2

Find the cube roots of 125(cos 288° + i sin 288°).


Correct result:

r =  5
α1 =  96 °
α2 =  216 °
α3 =  336 °

Solution:

r=1253=5
α1=288/3+0⋅ 360/3=96∘
α2=288/3+1⋅ 360/3=216∘
α3=288/3+2⋅360/3=336∘ z1=5(cos⁡96+isin⁡96) z2=5(cos⁡216∘+isin⁡216∘) z3=5(cos⁡336∘+isin⁡336∘)

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