Gasoline

35 l of gasoline is to be divided into four canisters so that in the third canister is 5 l less than the first canister, the fourth canister 10 l more than in the third canister, and the second canister half what in the first canister. How many liters of fuel are in each canister?

Final Answer:

a =  10 l
b =  5 l
c =  5 l
d =  15 l

Step-by-step explanation:

$$\begin{gathered} a+b+c+d=35 \\ c=a-5 \\ d=10+c \\ b=a/2 \\ a+b+c+d=35 \\ a+(a/2)+(a-5)+(10+c)=35 \\ a+(a/2)+(a-5)+(10+(a-5))=35 \\ 7a=70 \\ a=\frac{70}{7}=10 \\ a=10=10\text{l} \end{gathered}$$

$b=a/2=10/2=5\text{l}$

$c=a-5=10-5=5\text{l}$

$d=10+c=10+5=15\text{l}$

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