Temperature 21973

The aluminum container has an internal volume of 0.75 l at 20 °C. How does this volume change if the temperature increases by 55 °C? A = 24.10-6 K-1.

Correct answer:

V2 =  0.753 l

Step-by-step explanation:

t1=20 °C V1=0.75 l T=55 °C t2=t1+55=20+55=75 °C  α=24 1062.4105 1/K V2=V1 (1+3 α T)=0.75 (1+3 2.4105 55)=0.753 l



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