The bath

Dad poured 50 liters of water at 60°C into the tub. How much cold water must be added at 10°C to obtain a bath that has a temperature of 40°C?

Correct result:

V2 =  33.3333 l

Solution:

V1=50 l t1=60∘C t2=10∘C t=40∘C    V1⋅ t1+V2⋅ t2=(V1+V2)⋅ t 50⋅ 60+V2⋅ 10=(50+V2)⋅ 40  30V2=1000  V2=1003≐33.333333=33.3333 l

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