The bath

Dad poured 50 liters of water at 60°C into the tub. How much must he add cold water at 10°C to obtain a bath that has a temperature of 40°C?

Correct answer:

V2 =  33.3333 l

Step-by-step explanation:

V1=50 l t1=60 °C t2=10 °C t=40 °C  Q = m   c   (tt0) m = ρ V Q = ρ V   c (tt0)  Q1+Q2=Q ρ   V1   c (t1t0) + ρ   V2   c (t2t0) = ρ   (V1+V2)   c   (tt0) V1  (t1t0) + V2  (t2t0) = (V1+V2)   (tt0)  V1 t1+V2 t2=(V1+V2) t 50 60+V2 10=(50+V2) 40  30V2=1000  V2=301000=33.33333333  V2=310033.333333=33.3333 l

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Showing 2 comments:
Find the change in temperature if the temperature rises from −26°F to 15°F

Doktor Matematiky
Melinda - change of temps is 15 - (-26) = 41 °F

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