The bath

Dad poured 50 liters of water at 60°C into the tub. How much cold water must be added at 10°C to obtain a bath that has a temperature of 40°C?

Correct answer:

V2 =  33.3333 l

Step-by-step explanation:

V1=50 l t1=60 °C t2=10 °C t=40 °C  Q=m c (tt0) m=ρV Q=ρV c (tt0)  Q1+Q2=Q ρ V1 c (t1t0)+ρ V2 c (t2t0)=ρ (V1+V2) c (tt0) V1 (t1t0)+V2 (t2t0)=(V1+V2) (tt0)  V1 t1+V2 t2=(V1+V2) t 50 60+V2 10=(50+V2) 40  30V2=1000  V2=100333.333333=33.3333 l



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Showing 2 comments:
#
Melinda
Find the change in temperature if the temperature rises from −26°F to 15°F

#
Doktor Matematiky
Melinda - change of temps is 15 - (-26) = 41 °F

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