Water temperature cooling

We have 160 L of water at 67 °C; how many liters of cold water at 18 °C are needed to cool it to 39 °C?

Final Answer:

V2 =  213.3 l

Step-by-step explanation:

V1=160 l t1=67 °C t2=18 °C t3=39 °C  Q=V t  Q1+Q2=Q3  V1 t1+V2 t2=(V1+V2) t3 160 67+V2 18=(160+V2) 39  21V2=4480  V2=214480=213.33333333  V2=3640213.333333=213.3 l



Help us improve! If you spot a mistake, please let let us know. Thank you!







Tips for related online calculators
Do you have a linear equation or system of equations and are looking for a solution? Or do you have a quadratic equation?
Tip: Our volume units converter will help you convert volume units.

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: