Bath

In the bath is 30 liters of hot water. Then added 36 liters of cold water at temperature of 19 °C decreased temperature of water to 41 °C.

What was the initial temperature of the hot water?

Correct result:

t =  67.4 °C

Solution:

30t+36⋅19=(30+36)⋅41 t=67.4∘C30 t + 36 \cdot 19 = (30+36)\cdot 41 \ \\ t = 67.4 ^\circ \text{C}

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