There is 5 l of water with a temperature of 20°C in the bucket. We add 3 liters of hot water. The resulting temperature will be 30°C. What was the temperature of the hot water?

Correct answer:

t2 =  46.6667 °C

Step-by-step explanation:

V1=5 l t1=20 °C V2=3 l t3=30 °C  Q1+Q2 = Q3 m1 c t1+m2 c t2 = m3 c t3 m1 t1+m2 t2 = m3 t3  ρ V1 t1+ρ V2 t2 = ρ V3 t3  V1 t1+V2 t2=(V1+V2) t3 5 20+3 t2=(5+3) 30  3t2=140  t2=3140=46.66666667  t2=314046.666667=46.6667°C

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