Water mixing

There are 5 liters of water at 75 °C in the pot. How much water at 10 °C do we have to add to the resulting temperature of 55 °C?

Final Answer:

V2 =  2.2222 l

Step-by-step explanation:

t1=75 °C t2=10 °C t3=55 °C V1=5 l  V1 t1+t2 V2=t3 (V1+V2) 5 75+10 V2=55 (5+V2)  45V2=100  V2=45100=2.22222222  V2=9202.222222=2.2222 l



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