Water temperatures

To 25 liters of water at 50 °C we add 15 liters of water at a different temperature. How many °C should the water be colder than 50 °C so that 40 liters of the water obtained has a temperature 42.5 °C?

Correct answer:

x =  20 °C

Step-by-step explanation:

V1=25 l t1=50 °C V2=15 l t3=42.5 °C  Q1+Q2=Q3 m1 c t1+m2 c t2=m3 c t3 m1 t1+m2 t2=m3 t3  ρ V1 t1+ρ V2 t2=ρ V3 t3  V1 t1+V2 (50x)=(V1+V2) t3 25 50+15 (50x)=(25+15) 42.5  15x=300  x=20=20°C



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