Water mixing

We have 520 ml of hot water and 640 ml of water at 48°C. What is the temperature of approximately hot water when the resulting mixture has a temperature of 65°C?

Correct result:

x =  85.9231 °C

Solution:

$$\begin{gathered} 520\cdot x+640\cdot 48=65\cdot (520+640) \\ 520x=44680 \\ x={\displaystyle \frac{1117}{13}}\doteq 85.923077=85.9231^{\circ }\text{C} \end{gathered}$$

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