Chestnuts

Three divisions of nature protectors participated in the collection of chestnut trees.1. the division harvested 1250 kg, the 2nd division by a fifth more than the 1st division and the 3rd division by a sixth more than the second division. How many tons of chestnuts did they collect in total?

Result

x =  4.5 t

Solution:

a=1250 kg b=a+a/5=1250+1250/5=1500 kg c=b+b/6=1500+1500/6=1750 kg  d=a+b+c=1250+1500+1750=4500 kg  x=d→t=d/1000 t=4500/1000 t=4.5 t=92=4.5 ta=1250 \ \text{kg} \ \\ b=a + a/5=1250 + 1250/5=1500 \ \text{kg} \ \\ c=b + b/6=1500 + 1500/6=1750 \ \text{kg} \ \\ \ \\ d=a+b+c=1250+1500+1750=4500 \ \text{kg} \ \\ \ \\ x=d \rightarrow t=d / 1000 \ t=4500 / 1000 \ t=4.5 \ t=\dfrac{ 9 }{ 2 }=4.5 \ \text{t}

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