Flywheel

Flywheel turns 450 rev/min (RPM). Determine the magnitude of the normal acceleration of the flywheel point which are at a distance of 10 cm from the rotation axis.

Result

g =  222.07 m/s2

Solution:

g=10/100 (2π 450/60)2=222.07 m/s2g=10/100 \cdot \ (2 \pi \cdot \ 450/60)^{ 2 }=222.07 \ \text{m/s}^2



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