Flywheel

Flywheel turns 450 rev/min (RPM). Determine the magnitude of the normal acceleration of the flywheel point which are at a distance of 10 cm from the rotation axis.

Correct result:

g =  222.07 m/s²

Solution:

$g=10\mathrm{/}100\cdot (2\pi \cdot 450\mathrm{/}60{)}^2=222.07{\text{m/s}}^2$

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