Engine pulley

The engine has a 1460 rev/min (RPM). The disc diameter is 350 mm. What will be the peripheral disc speed in RPM? Pulleys on the engine have a diameter of 80 mm, and a disc has a diameter of 160 mm.

Final Answer:

n₂ =  730 1/min
n₃ =  13.3779 m/s

Step-by-step explanation:

$$\begin{gathered} D_1=80\text{mm} \\ {D}_2=160\text{mm} \\ {n}_2=1460\cdot D_1/D_2=1460\cdot 80/160=7301\text{/min} \end{gathered}$$

$$\begin{gathered} D_3=350\text{mm}\to \text{m}=350:1000\text{m}=0.35\text{m} \\ {n}_3=\pi \cdot D_3\cdot n_2/60=3.1416\cdot 0.35\cdot 730/60=13.3779\text{m/s} \end{gathered}$$

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