Engine pulley

The engine has a 1460 rev / min (RPM). Disc diameter is 350 mm. What will be the disc peripheral speed in RPM? Pulleys on the engine has diameter 80mm, on a disc has diameter 160mm.

Correct result:

n2 =  730 1/min
n3 =  13.3779 m/s

Solution:

D1=80 mm D2=160 mm  n2=1460 D1/D2=1460 80/160=730 1/min
D3=350 mm m=350/1000  m=0.35 m n3=π D3 n2/60=3.1416 0.35 730/60=13.3779 m/s



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