The four

The four pirates divided 65 coins into each other. They were sorted by age, the youngest receiving the least number of coins, each half more than the previous one. How many coins did the oldest pirate receive?

Final Answer:

a =  27

Step-by-step explanation:


a+a/1.5+a/(1.5·1.5)+a/(1.5·1.5·1.5) =65

2.407407a = 65


a = 65/2.40740741 = 27

a = 27

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algebraarithmeticnumbersUnits of physical quantitiesGrade of the word problem

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