# Pump

What power has a pump output to move 4853 hl of water to a height of 31 m for 8 hours?

Result

P =  5124 W

#### Solution:

$P = \dfrac{mgh}{t} = \dfrac{ 100 \cdot 4853 \cdot 9.81 \cdot 31}{ 8 \cdot 3600} = 5124 \ \text{W}$

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