On the farm

On the farm were housed 70 heads of cattle with food supply for 180 days. After 60 days, 10 head of cattle sold, and for the next 30 days they sold 10 more. How many days is sufficient supply of feed for the remaining cattle?

Result

x =  132 d

Solution:

x=(70 18070 60(7010) 30)/(701010)=132 dx=(70 \cdot \ 180 - 70 \cdot \ 60-(70-10) \cdot \ 30)/(70-10-10)=132 \ \text{d}



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