Hikers meeting

Hiker A travels a certain distance in 5 hours and 24 minutes. Hiker B travels the same distance in 6 hours and 45 minutes. After what walking time will they meet if they simultaneously start opposite each other on the same route? (To the route that everyone went alone before.)

Final Answer:

t =  3 h

Step-by-step explanation:

$$\begin{gathered} t_1=5:24=5hr24min=5+\frac{24}{60}=5.4hr=5.4 \\ {t}_2=6:45=6hr45min=6+\frac{45}{60}=6.75hr=6.75 \\ s=\frac{1}{t_1}+\frac{1}{t_2}=\frac{1}{5.4}+\frac{1}{6.75}=\frac{1}{3}\doteq 0.3333 \\ s\cdot t=1 \\ t=1/s=1/0.3333=3\text{h} \end{gathered}$$

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