Different 25431

Tickets have 9 numbered windows.
How many different codes can be set for each other if 3 or 4 windows are punched?

Correct answer:

n =  210

Step-by-step explanation:

C3(9)=(39)=3!(93)!9!=321987=84  C4(9)=(49)=4!(94)!9!=43219876=126  n=(39)+(49)=84+126=210

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