Cyclist distance calculation

The cyclist rode 44 km and 400 m in three days. In the first hour, he covered the course 5% longer than in the second hour, and in the third hour, he covered 1 km more than in the first hour. How many km did he travel in the third hour?

Final Answer:

c =  15.7 km

Step-by-step explanation:

$$\begin{gathered} s=44+400/1000=\frac{222}{5}=44.4\text{km} \\ r=100\%+5\%=1+\frac{5}{100}=1.05 \\ a+b+c=s \\ a=r\cdot b \\ c=1km+a=1+r\cdot b \\ r\cdot b+b+(1+r\cdot b)=s \\ 1.05\cdot b+b+(1+1.05\cdot b)=44.4 \\ 3.1b=43.4 \\ b=\frac{43.4}{3.1}=14 \\ b=14 \\ a=r\cdot b=1.05\cdot 14=\frac{147}{10}=14.7 \\ c=1+r\cdot b=1+1.05\cdot 14=15.7\text{km} \end{gathered}$$

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