# Ace

The length of segment AB is 24 cm and the point M and N divided it into thirds. Calculate the circumference and area of this shape.

Result

o =  75.398 cm
S =  150.796 cm2

#### Solution:

$o=2 \pi \cdot \ (24/3)+2 \pi \cdot \ (24/3/2)=75.398 \ \text{cm}$
$S=\pi \cdot \ (24/3)^2-\pi \cdot \ (24/3/2)^2=150.796 \ \text{cm}^2$

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