Coils of transformer

The primary coil of the transformer has 400 turns, a current of 1.5 A passes through it and is connected to a voltage of 220 V. For the secondary coil, find the voltage, current, and a number of turns if the transformation ratio k = 0.1.

Correct result:

U2 =  22 V
I2 =  0.15 A
N2 =  40

Solution:

N1=400 I1=1.5 A U1=220 V k=0.1  k=N2N1=U2U1=I2I1  U2=k U1=0.1 220=22 V
I2=I1 k=1.5 0.1=320=320 A=0.15 A
N2=k N1=0.1 400=40



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Showing 2 comments:
#
Math student
i think the value of I2=0.15A

#
Math student
k=i2/i1  which is wrong

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