Hexagonal pyramid

Find the volume of a regular hexagonal pyramid, the base edge of which is 12 cm long and the side edge 20 cm.

Correct result:

V =  1995.3225 cm3

Solution:

a=12 cm s=20 cm  S0=3/4⋅ a2=3/4⋅ 122=36 3 cm2≐62.3538 cm2 S1=6⋅ S0=6⋅ 62.3538=216 3 cm2≐374.123 cm2  s2=h2+a2 h=s2−a2=202−122=16 cm  V=13⋅ S1⋅ h=13⋅ 374.123⋅ 16=1995.3225 cm3

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