Foot in bus

It was 102 people on the bus. 28 girls had two dogs. A 11 girls had one dog.
At the next stop seceded 5 dogs (even with their owners). They got two boys together with three dogs. The bus drove one driver.
How many foot were in bus?

Result

n =  458

Solution:

a=102−5+2=99 d=28⋅ 2+11⋅ 1−5+3=65  n=2⋅ a+4⋅ d=2⋅ 99+4⋅ 65=458a=102-5+2=99 \ \\ d=28 \cdot \ 2+11 \cdot \ 1-5+3=65 \ \\ \ \\ n=2 \cdot \ a+4 \cdot \ d=2 \cdot \ 99+4 \cdot \ 65=458

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