# Air draft

The numbers 1,2,3,4,5 are written on five tickets on the table. Air draft randomly shuffled the tickets and composed a 5-digit number from them. What is the probability that he passed:
and, the largest possible number
b, the smallest possible number
c, a number divisible by five
d, even number
e, odd number
f, a number divisible by three
g, a number divisible by nine

Correct result:

a =  0.0083
b =  0.0083
c =  0.2
d =  0.4
e =  0.6
f =  1
g =  0

#### Solution:

$a=\frac{1}{5!}=\frac{1}{120}=0.0083$
$b=a=0.0083=\frac{1}{120}$

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