Cylindrical 30331

Calculate the area of sheet metal needed to make a closed cylindrical vessel with a radius of 2.5 m and a height of 1.2 m if the joints and waste count for 6%.

Final Answer:

S =  61.6066 m²

Step-by-step explanation:

$$\begin{gathered} r=2.5\text{m} \\ h=1.2\text{m} \\ q=100\%+6\%=1+\frac{6}{100}=1.06 \\ {S}_1=\pi \cdot r^2=3.1416\cdot 2.5^2\doteq 19.635{\text{m}}^2 \\ {S}_2=2\pi \cdot r\cdot h=2\cdot 3.1416\cdot 2.5\cdot 1.2\doteq 18.8496{\text{m}}^2 \\ S=q\cdot (2\cdot S_1+S_2)=1.06\cdot (2\cdot 19.635+18.8496)=61.6066{\text{m}}^2 \end{gathered}$$

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