Area and perimeter of rectangle

The content area of the rectangle is 3000 cm2, one dimension is 10 cm larger than the other. Determine the perimeter of the rectangle.

Correct result:

o =  220 cm

Solution:

3000=ab a=b+10  3000=b∗(b+10)  3000=b⋅ (b+10) −b2−10b+3000=0 b2+10b−3000=0  p=1;q=10;r=−3000 D=q2−4pr=102−4⋅1⋅(−3000)=12100 D>0  b1,2=−q±D2p=−10±121002 b1,2=−10±1102 b1,2=−5±55 b1=50 b2=−60   Factored form of the equation:  (b−50)(b+60)=0  b=b1=50=50 cm a=b+10=50+10=60 cm  o=2⋅ (a+b)=2⋅ (60+50)=220 cm

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