The length of the inner edge of the running oval is 400 m. The straight sections measure 90 m. Calculate the dimensions of the oval - the rectangle where this oval can fit.

Correct result:

a =  160.0282 m
b =  70.0282 m


o=400 m r=90 m o2=o2 r=4002 90=220 m  o2=π D  D=o2/π=220/3.141670.0282 m  a=r+D=90+70.0282=160.0282 m
b=D=70.0282=70.0282 m

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