Acid solution

By adding 250 grams of a 96% sulfuric acid solution to its 3% solution, we changed its initial concentration to 25%. How many grams of 3% of the acid were used for dilution?

Final Answer:

x =  806.8182

Step-by-step explanation:


250·0.96+x·0.03 = 0.25·(x+250)

0.22x = 177.5


x = 177.5/0.22 = 806.81818182

x = 8875/11 ≈ 806.818182

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