Acid solution

By adding 250 grams of a 96% solution of sulfuric acid to its 3% solution its initial concentration was changed to 25%. How many grams of 3% of the acid were used for dilution?

Correct result:

x =  806.8182

Solution:


250•0.96+x•0.03 = 0.25•(x+250)

0.22x = 177.5

x = 8875/11 ≈ 806.818182

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