Acids

64% acid is made from the same acid of two different concentrations. The amount of weaker acid to the stronger acid is in ratio 2:1.

What was the concentration of the weaker acid if the stronger had 98% concentration?

Final Answer:

c =  47 %

Step-by-step explanation:

$$\begin{gathered} a:b=2:1 \\ \frac{a}{b}=\frac{2}{1} \\ ak+b\cdot 0.98=0.64(a+b) \\ 2\cdot k+1\cdot 0.98=0.64\cdot (2+1) \\ 2k=0.94 \\ k=\frac{0.94}{2}=0.47 \\ k=\frac{47}{100}=0.47 \\ c=100\cdot k=100\cdot 0.47=47\% \end{gathered}$$

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