Acid

The barrel is 199 liters of 38% acid. How many percent acids occur when 61 liters revoke and replace with the same amount of water?

Correct answer:

acid concentration =  26.4 %

Step-by-step explanation:

$c={\displaystyle \frac{199-61}{199}}\cdot 38=26.4\mathrm{\%}$

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