# Acid

The barrel is 199 liters of 38% acid. How many percent acids occur when 61 liters revoke and replace with the same amount of water?

### Correct answer:

acid concentration =  26.4 %

### Step-by-step explanation:

$c=\frac{199-61}{199}\cdot 38=26.4\mathrm{%}$ We will be pleased if You send us any improvements to this math problem. Thank you! Tips to related online calculators
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