Acid

The barrel is 79 liters of 60% acid. How many percent of acids occur when 4 liters are revoked and replaced with the same amount of water?

Final Answer:

c =  57 %

Step-by-step explanation:

V1=79 l V2=4 l  p=60%=10060=53=0.6  c=100 V1V1V2 p=100 79794 0.6=57%



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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsnumbersUnits of physical quantitiesthemes, topicsGrade of the word problem

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